document.write( "Question 498837: divide 135 into three parts in the ratio 3:5:7 \n" ); document.write( "
Algebra.Com's Answer #337213 by Theo(13342)\"\" \"About 
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3x + 5x + 7x = 135
\n" ); document.write( "15x = 135
\n" ); document.write( "x = 9
\n" ); document.write( "3x = 27
\n" ); document.write( "5x = 45
\n" ); document.write( "7x = 63
\n" ); document.write( "15x = 27 + 45 + 63 = 135
\n" ); document.write( "the parts are:
\n" ); document.write( "27, 45, 63
\n" ); document.write( "they are in the ratio 3:5:7
\n" ); document.write( "divide each part by 9 and you get:
\n" ); document.write( "3, 5, 7
\n" ); document.write( "the parts of 37, 45, 63 can be expressed in the ratio of 3, 5, 7 by use of the ratio formula of:
\n" ); document.write( "27/3 = 45/5 = 63/7
\n" ); document.write( "this reads as:
\n" ); document.write( "27 is to 3 as 45 is to 5 as 63 is to 7.
\n" ); document.write( "perform the calculations and you get:
\n" ); document.write( "9 = 9 = 9
\n" ); document.write( "this confirms the ratio has been preserved using these numbers.
\n" ); document.write( "the sum has also been preserved, so the numbers are good.\r
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