document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498819>Question 498819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> paul and frank are on the same path 39.15 miles apart. they are going to ride their bike towards each other until they meet. frank starts pedaling 1.5 hours before paul. paul rides 1.8 miles per hour faster than frank. if they meet 3 hours after paul starts riding, find the speed of each biker. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337203 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337203\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> paul and frank are on the same path 39.15 miles apart. they are going to ride their bike towards each other until they meet. frank starts pedaling 1.5 hours before paul. paul rides 1.8 miles per hour faster than frank. if they meet 3 hours after paul starts riding, find the speed of each biker.\r<BR>\n" );
document.write( "\n" );
document.write( "Frank speed = x mph<BR>\n" );
document.write( "Paul speed = x+1.8 mph<BR>\n" );
document.write( "Frank leaves 1.5 hours early\r<BR>\n" );
document.write( "\n" );
document.write( "distance traveled by Frank in in 1.5 hours = 1.5x<BR>\n" );
document.write( "so when Paul starts Frank is (39.15-1.5x) miles away\r<BR>\n" );
document.write( "\n" );
document.write( "they are pedalling towards each other<BR>\n" );
document.write( "so add up the speeds\r<BR>\n" );
document.write( "\n" );
document.write( "2x+1.8\r<BR>\n" );
document.write( "\n" );
document.write( "t= d/r<BR>\n" );
document.write( "t= 3 hours<BR>\n" );
document.write( "d= (39.15-1.5x)<BR>\n" );
document.write( "r= 2x+1.8<BR>\n" );
document.write( "3= (39.15-1.5x)/(2x+1.8)\r<BR>\n" );
document.write( "\n" );
document.write( "6x+5.4 = 39.15-1.5x<BR>\n" );
document.write( "7.5x=39.15-5.4<BR>\n" );
document.write( "7.5x=33.75<BR>\n" );
document.write( "x=4.5<BR>\n" );
document.write( "Frank Speed = 4.5 mph<BR>\n" );
document.write( "Paul speed = 6.3 mph\r<BR>\n" );
document.write( "\n" );
document.write( "m.ananth@hotmail.ca </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );