document.write( "Question 498796: How do I solve C = 6,000/200 - 2x
\n" ); document.write( "x=75%
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Algebra.Com's Answer #337181 by Theo(13342)\"\" \"About 
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x = 75% = .75
\n" ); document.write( "formula becomes:
\n" ); document.write( "C = 6000 / 200 - 2*.75 which becomes:
\n" ); document.write( "C = 6000 / 200 - 1.5
\n" ); document.write( "now the question becomes:
\n" ); document.write( "is it (6000 / 200) - 1.5
\n" ); document.write( "or is it 6000 / (200 - 1.5)
\n" ); document.write( "you'll get a different answer depending on what the original question intended.
\n" ); document.write( "was this equation given to you as such, or was it a word problem that you had to develop an equation for?
\n" ); document.write( "if so, what does the word problem ask?
\n" ); document.write( "75% is not usually used as the value for x.
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