document.write( "Question 498804: The sum of the age of Dave and Ted is 48 yrs.Eight years from now Ted will be three times Dave age. Find their present age. \n" ); document.write( "
Algebra.Com's Answer #337179 by kim09(1)\"\" \"About 
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let:
\n" ); document.write( "x-Dave
\n" ); document.write( "y-ted\r
\n" ); document.write( "\n" ); document.write( " the sum of the ages of Dave and ted is 48.
\n" ); document.write( "8 years from now ted will be 3 times Dave's age.
\n" ); document.write( "Find their present ages.\r
\n" ); document.write( "\n" ); document.write( "Equations:
\n" ); document.write( "x + y = 48
\n" ); document.write( "(y+8) = 3(x+8)\r
\n" ); document.write( "\n" ); document.write( "Substitute for y and solve for \"x\":
\n" ); document.write( "(x + 48-x) = 3x+24
\n" ); document.write( "3x = 48-24
\n" ); document.write( "3x = 24
\n" ); document.write( "x = 8 (Dave's age now)\r
\n" ); document.write( "\n" ); document.write( "Since x+y = 48, ted is 40 yrs old\r
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