document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498748>Question 498748</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If have a 50 lb. bag of dry powder that is to be mixed with 6.5 quarts of water, but I only need to mix a very small amount of the product. <BR>\n" );
document.write( "If I want to use only 1/2 lb. of powder, how much water would I use?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337177 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337177\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of water needed\r<BR>\n" );
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document.write( "Now we can set up a simple ratio:<BR>\n" );
document.write( "50 is to 6.5 as 0.5 is to x and we write this as follows:<BR>\n" );
document.write( "50/6.5=0.5/x  multiply each term by 6.5x (or simply cross-multiply)<BR>\n" );
document.write( "50x=3.25<BR>\n" );
document.write( "x= 0.065 qts per 1/2lb----amount of water needed<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "(100)*(1/2)gal=50gal<BR>\n" );
document.write( "100*0.065=6.5 qts\r<BR>\n" );
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document.write( "Hope this helps---ptaylor  </SPAN>\n" );
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