document.write( "Question 498795: -2 3
\n" ); document.write( "(p/q) * 121/100=1. find (p/q)
\n" ); document.write( "i have put power of -2 on (p/q)in first case and power of 3 in second case. \n" ); document.write( "

Algebra.Com's Answer #337173 by Alan3354(69443) $\"\"$ $\"About$

You can put this solution on YOUR website!
(p/q)^-2* 121/100=1. find (p/q)^3
\n" ); document.write( "----------
\n" ); document.write( " $\"%28p%2Fq%29%5E-2%2A+%28121%2F100%29+=+1\"$
\n" ); document.write( " $\"%28121%2F100%29+=+%28p%2Fq%29%5E2\"$
\n" ); document.write( " $\"p%2Fq+=+11%2F10\"$
\n" ); document.write( " $\"%28p%2Fq%29%5E3+=+1331%2F1000\"$
\n" ); document.write( " \n" ); document.write( "

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