document.write( "Question 50644: simplify: 4sqrt81*x^6*y^8\r
\n" ); document.write( "\n" ); document.write( "I hope I wrote that right! It's 4square root 81x to the 6th y to the 8th.
\n" ); document.write( "Thanks so much!!!!
\n" ); document.write( "Carolyn:):)
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Algebra.Com's Answer #33717 by rapaljer(4671)\"\" \"About 
You can put this solution on YOUR website!
Are you sure it is 4 times the square root of this quantity? Without seeing the problem written, my guess is that you mean the 4th root of this quantity.\r
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\n" ); document.write( "\n" ); document.write( "This is the difference:\r
\n" ); document.write( "\n" ); document.write( "4 times the square root: \"4%2A+sqrt%2881x%5E6%2Ay%5E8%29+\"
\n" ); document.write( "Fourth root of quantity: \"root%284%2C+81x%5E6%2Ay%5E8%29\"\r
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\n" ); document.write( "\n" ); document.write( "The square root is easiest so I'll do what you asked:\r
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\n" ); document.write( "\n" ); document.write( "First, you will have to know that 81 is a perfect square (9^2=81), and when you take square roots of variables raised to a power, you must divide the exponents by 2. Now,\r
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\n" ); document.write( "\n" ); document.write( "\"4%2A+sqrt%2881x%5E6%2Ay%5E8%29+\"
\n" ); document.write( "\"+4%2A9x%5E3%2Ay%5E4\"
\n" ); document.write( "\"+36x%5E3%2Ay%5E4\"\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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