document.write( "Question 497909: Hi, this is review in my Calculus book... Solve: log(base x) (2x-3)=2 for x.
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document.write( "I tried doing this:
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document.write( "2x-3=x^2
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document.write( "x^2-2x+3=0
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document.write( "(x-3)(x+1)=0
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document.write( "So x = 3 and x = 1.
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document.write( "But then I thought it might be False since if you put 3 and 1 into the first eqation that it wouldn't come out to 2.
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document.write( "Thanks for helping \n" );
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Algebra.Com's Answer #337168 by lwsshak3(11628) ![]() You can put this solution on YOUR website! Solve: log(base x) (2x-3)=2 for x \n" ); document.write( "Base(x) raised to log of number(2)=number(2x-3) \n" ); document.write( "2x-3=x^2 \n" ); document.write( "x^2-2x+3=0 \n" ); document.write( "(x-3)(x+1)=0 \n" ); document.write( "So x = 3 and x = 1 \n" ); document.write( "** \n" ); document.write( "You got the basic log quadratic equation correct, but you goofed up on its solution. \n" ); document.write( "a=1, b=-2, c=3 \n" ); document.write( "The discriminant, √(b^2-4ac)=√(4-4*1*3)=√(4-12)=√-8 \n" ); document.write( "There is no solution, because x is not a real number \n" ); document.write( ".. \n" ); document.write( "Good Luck on your calculus class! \n" ); document.write( " |