document.write( "Question 498675: hana walked from her home to a bicycle repair shop at a rate of 3.5mph and then rode her bicycle home at a rate of 14mph if the total time spent traveling was 1hour how far from hanas home is the repair shop \n" ); document.write( "

Algebra.Com's Answer #337115 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"d\"$ = distance to repair shop
\n" ); document.write( "walking:
\n" ); document.write( " $\"+d+=+3.5%2At+\"$
\n" ); document.write( "With bicycle:
\n" ); document.write( " $\"+d+=+14%2A%281+-+t%29+\"$
\n" ); document.write( " $\"+3.5t+=+14%2A%281+-+t%29+\"$
\n" ); document.write( " $\"+3.5t+=+14+-+14t+\"$
\n" ); document.write( " $\"+17.5t+=+14+\"$
\n" ); document.write( " $\"+t+=+.8+\"$
\n" ); document.write( "and, since
\n" ); document.write( " $\"+d+=+3%2C5t+\"$
\n" ); document.write( " $\"+d+=+3.5%2A.8+\"$
\n" ); document.write( " $\"+d=+2.8+\"$
\n" ); document.write( "The distance to the repair shop is 2.8 mi
\n" ); document.write( "check:
\n" ); document.write( " $\"+d+=+14%2A%281+-+t%29+\"$
\n" ); document.write( " $\"+d+=+14%2A%281+-+.8%29+\"$
\n" ); document.write( " $\"+d+=+14%2A.2+\"$
\n" ); document.write( " $\"+d+=+2.8+\"$ mi
\n" ); document.write( "OK \n" ); document.write( "

\n" );