document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498085>Question 498085</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a square is drawn inside of a circle such that its four corners are touching the interior edge of the circle, what is the ratio of the area of the square to the area of the circle? You should calculate and express your answer as a decimal ratio (i.e. .328 : 1) <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #337044 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=337044\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> If a square is drawn inside of a circle such that its four corners are touching the interior edge of the circle, what is the ratio of the area of the square to the area of the circle? <BR>\n" );
document.write( "You should calculate and express your answer as a decimal ratio<BR>\n" );
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document.write( "Let s = the side of the square<BR>\n" );
document.write( "then<BR>\n" );
document.write( "s^2 = area of the square<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282s%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%282s%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = the diagonal of the square, and the diameter of the circle<BR>\n" );
document.write( "therefore<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%282s%5E2%29%2F2 ALIGN=MIDDLE  ALT=\"sqrt%282s%5E2%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = the radius of the circle<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A%28sqrt%282s%5E2%29%2F2%29%5E2 ALIGN=MIDDLE  ALT=\"pi%2A%28sqrt%282s%5E2%29%2F2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A%28%282s%5E2%29%2F4%29 ALIGN=MIDDLE  ALT=\"pi%2A%28%282s%5E2%29%2F4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=pi%2A%28%28s%5E2%29%2F2%29 ALIGN=MIDDLE  ALT=\"pi%2A%28%28s%5E2%29%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = the area of the circle<BR>\n" );
document.write( ":<BR>\n" );
document.write( "Ratio of the area of the square to the area of the circle<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2%2F%28pi%2A%28s%5E2%2F2%29%29%29 ALIGN=MIDDLE  ALT=\"s%5E2%2F%28pi%2A%28s%5E2%2F2%29%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=s%5E2%2A%282%2F%28pi%2As%5E2%29%29%29 ALIGN=MIDDLE  ALT=\"s%5E2%2A%282%2F%28pi%2As%5E2%29%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "Cancel s^2<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2F%28pi%29 ALIGN=MIDDLE  ALT=\"2%2F%28pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F%28pi%2F2%29 ALIGN=MIDDLE  ALT=\"1%2F%28pi%2F2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 1:1.5707, square area:circle area<BR>\n" );
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