document.write( "Question 498380: One runner finishes a race in one hour. A second runner finishes 20 minutes later. If the faster runner is 2mph more than the slower runner, find the rate of each runner. How do I set this up? \n" ); document.write( "
Algebra.Com's Answer #337015 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You need an equation for each runner
\n" ); document.write( "Let \"s\" = speed of slower runner in mi/hr
\n" ); document.write( "Let \"d\" = the distance of the race
\n" ); document.write( "given:
\n" ); document.write( "\"+s+%2B+2+\" = speed of faster runner
\n" ); document.write( "\"+1+\" hr = faster runner's time
\n" ); document.write( "\"+4%2F3+\" hr = slower runner's time
\n" ); document.write( "---------------------------
\n" ); document.write( "Slower runner:
\n" ); document.write( "\"+d+=+s%2A%284%2F3%29+\"
\n" ); document.write( "Faster runner:
\n" ); document.write( "\"+d+=+%28+s+%2B+2+%29%2A1+\"
\n" ); document.write( "-----------------
\n" ); document.write( "\"+%284%2F3%29%2As+=+s+%2B+2+\"
\n" ); document.write( "Multiply both sides by \"3\"
\n" ); document.write( "\"+4s+=+3s+%2B+6+\"
\n" ); document.write( "\"+s+=+6+\"
\n" ); document.write( "\"+s+%2B+2+=+8+\"
\n" ); document.write( "The faster runner's speed is 8 mi/hr
\n" ); document.write( "The slower runner's speed is 6 mi/hr
\n" ); document.write( "
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