document.write( "Question 498157: An athlete runs 10 miles and then walks home. The trip home takes 1 hour longer than it took to run that distance. If the athlete runs 5 miles per hour faster than she walks, what are her average running and walking speeds? \n" ); document.write( "
Algebra.Com's Answer #337008 by ankor@dixie-net.com(22740)\"\" \"About 
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An athlete runs 10 miles and then walks home.
\n" ); document.write( " The trip home takes 1 hour longer than it took to run that distance.
\n" ); document.write( " If the athlete runs 5 miles per hour faster than he walks, what are his average running and walking speeds?
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\n" ); document.write( "let s = his walking speed
\n" ); document.write( "then
\n" ); document.write( "(s+5) = his running speed
\n" ); document.write( ":
\n" ); document.write( "Write a time equation; time = dist/speed
\n" ); document.write( ":
\n" ); document.write( "Run speed = Walk speed + 1 hr
\n" ); document.write( "\"10%2F%28%28s%2B5%29%29\" = \"10%2Fs\" + 1
\n" ); document.write( ":
\n" ); document.write( "multiply by s(s+5), results
\n" ); document.write( "10s = 10(s+5) + s(s+5)
\n" ); document.write( ":
\n" ); document.write( "10s = 10s + 50 + s^2 + 5s
\n" ); document.write( "combine this as a quadratic equation
\n" ); document.write( "s^2 + 5s - 50 = 0
\n" ); document.write( "Factors to:
\n" ); document.write( "(s+10)(s-5) = 0
\n" ); document.write( "positive solution
\n" ); document.write( "s = 5 mph is his walking speed
\n" ); document.write( "then, obviously, 10 mph is his running speed
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\n" ); document.write( ":
\n" ); document.write( "confirm this. find the actual times
\n" ); document.write( "10/5 = 2hr
\n" ); document.write( "10/10= 1hr
\n" ); document.write( "-------------
\n" ); document.write( "diff: 1 hr\r
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