document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498266>Question 498266</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Terri and Judy run a lawn mowing business.  If Terri can mow a large lawn in 8 hours and Judy can mow the same lawn in 12 hours, how long will it take them together to mow the lawn? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336985 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336985\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Terri and Judy run a lawn mowing business.  If Terri can mow a large lawn in 8 hours and Judy can mow the same lawn in 12 hours, how long will it take them together to mow the lawn?<BR>\n" );
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document.write( "Terri does 1/8 lawn per hour<BR>\n" );
document.write( "Judy does 1/2 lawn per hour<BR>\n" );
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document.write( "Together, they do 1/8 + 1/12 per hour = 5/24 lawn/hr<BR>\n" );
document.write( "--> 24/5 hr/lawn<BR>\n" );
document.write( "= 4.8 hour/lawn\r<BR>\n" );
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document.write( " </SPAN>\n" );
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