document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50602>Question 50602</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0618250204/algebrahomeworkh>Algebra 2</A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> I'm trying to assist my daughter in solving this problem and can't recall how to deal with a complex fraction.  It's been many years.  Thank you for your assistance.\r<BR>\n" );
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document.write( "5(x/y)-x  when x=6 and y= 2/3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33698 by </B><A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><B>tutorcecilia(2152)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=tutorcecilia><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=tutorcecilia><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33698\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5(x/y)-x [Substitute 6 for x and 2/3 for y]<BR>\n" );
document.write( "5(6)/(2/3)-(6) [Simplify]<BR>\n" );
document.write( "5(6)/(2/3)-(6)<BR>\n" );
document.write( "(30)/(2/3) -(6)<BR>\n" );
document.write( "(30)(3/2)-(6)<BR>\n" );
document.write( "90/2 -(6)<BR>\n" );
document.write( "90/2 -(6)(2)/2<BR>\n" );
document.write( "90-12/2<BR>\n" );
document.write( "78/2<BR>\n" );
document.write( "39 </SPAN>\n" );
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