document.write( "Question 498215: which is a possible solution of
\n" ); document.write( "6 + sqrt(3x^4 + 1) = 10 - 2x^2\r
\n" ); document.write( "\n" ); document.write( "the answer is -sqrt(15) but i don't know the solution
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Algebra.Com's Answer #336975 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the answer is:\r
\n" ); document.write( "\n" ); document.write( "possible solutions to the given equation are:
\n" ); document.write( "x = +/- 1
\n" ); document.write( "or:
\n" ); document.write( "x = +/- sqrt(15)
\n" ); document.write( "here's how this equation is solved:
\n" ); document.write( "original equation is:
\n" ); document.write( "6 + sqrt(3x^4 + 1) = 10 - 2x^2
\n" ); document.write( "subtract 6 from both sides of the equation to get:
\n" ); document.write( "sqrt(3x^4 + 1) = 4 - 2x^2
\n" ); document.write( "square both sides of the equation to get:
\n" ); document.write( "3x^4 + 1 = (4 - 2x^2)^2
\n" ); document.write( "simplify to get:
\n" ); document.write( "3x^4 + 1 = 4x^4 - 16x^2 + 16
\n" ); document.write( "subtract 3x^4 from both sides of the equation and subtract 1 from both sides of the equation to get:
\n" ); document.write( "0 = x^4 - 16x^2 + 15
\n" ); document.write( "this is the same as:
\n" ); document.write( "x^4 - 16x^2 + 15 = 0
\n" ); document.write( "let y = x^2 to get:
\n" ); document.write( "y^2 - 16y + 15 = 0
\n" ); document.write( "this is a quadratic equation that can be factored with:
\n" ); document.write( "(y - 1) * (y - 15) = 0
\n" ); document.write( "this gets:
\n" ); document.write( "y = 1
\n" ); document.write( "or:
\n" ); document.write( "y = 15
\n" ); document.write( "since y = x^2, then this is the same as:
\n" ); document.write( "x^2 = 1
\n" ); document.write( "or:
\n" ); document.write( "x^2 = 15
\n" ); document.write( "take the square root of both sides of these equations and you get:
\n" ); document.write( "x = +/- 1
\n" ); document.write( "x = +/- sqrt(15)
\n" ); document.write( "these are possible solutions of the original equation.
\n" ); document.write( "this does not mean that they are actual solutions to the original equation.
\n" ); document.write( "to see if we did the factoring right, we substitute in the revised equations that got us to this point.
\n" ); document.write( "that equation is:
\n" ); document.write( "3x^4 + 1 = (4 - 2x^2)^2
\n" ); document.write( "if we substitute + 1 for x in that equation, we get 0 as we should.
\n" ); document.write( "if we substitute - 1 for x in that equation, we get 0 as we should.
\n" ); document.write( "if we substitute sqrt(15) for x in that equation, we get 0 as we should.
\n" ); document.write( "if we substitute sqrt(15) for x in that equation, we get 0 as we should.
\n" ); document.write( "this means that our solution is good for the equation that we evaluated it at.
\n" ); document.write( "we need, however, to confirm that these are solutions to the original equation.
\n" ); document.write( "the original equation is:
\n" ); document.write( "6 + sqrt(3x^4 + 1) = 10 - 2x^2
\n" ); document.write( "if this equation is equal, then we can subtract (10-2x^2) from both sides of the equation to get:
\n" ); document.write( "6 + sqrt(3x^4 + 1) - (10 - 2x^2) = 0
\n" ); document.write( "if we substitute + 1 for x in that equation, we get 0 as we should.
\n" ); document.write( "if we substitute - 1 for x in that equation, we get 0 as we should.
\n" ); document.write( "if we substitute + sqrt(15) for x in that equation, we get 52 which we should not have gotten if sqrt(15) was a solution. apparently it is not.
\n" ); document.write( "if we substitute - sqrt(15) for x in that equation, we get 52 which we should not have gotten if sqrt(15) was a solution. apparently it is not.
\n" ); document.write( "while +/- sqrt(15) were possible solutions to the original equations, it turned out that they were not solutions to the original equations.
\n" ); document.write( "while +/- 1 were possible solutions to the original equations, it turned out that they were actually solutions to the original equations.
\n" ); document.write( "the answer is that the solutions to the original equation given is:
\n" ); document.write( "x = +/- 1.
\n" ); document.write( "if we graph the original equation and the revised equation, this is what we get:
\n" ); document.write( "
\n" ); document.write( "you can see that the revised equation has roots at +/- 1 and +/- sqrt(15).
\n" ); document.write( "you can also see that the original equation only has roots at +/- 1.
\n" ); document.write( "that is why +/- 1 was a solution to the original equation, but +/- sqrt(15) was not.
\n" ); document.write( "in this graph, there are vertical lines at x = +/- sqrt(15) and x = +/- 1 to show you that the revised equation has roots in both places (y = 0) while the original equation only has roots at x = +/- 1 and does not have roots at y = +/- sqrt(15).
\n" ); document.write( "the fact that the graph of the revised equation and the graph of the original equation intersect at some other point besides the 0 point is meaningless to the problem.
\n" ); document.write( "the problem was to find the solution to the original equation.
\n" ); document.write( "if we had graphed the original equation by itself, we would only have seen roots at +/- 1.
\n" ); document.write( "that was sufficient to solve the problem.
\n" ); document.write( "the fact that we created the revised equation to solve the original equation was a matter of convenience to make a 4th degree equation equivalent to a second degree equation, which we know how to solve because it's a quadratic equation.
\n" ); document.write( "we got possible solutions, but there was no guarantee that a solution to the revised equation would also be a solution to the original equation. we did preserve the equality, but to say that these 2 equations are identical would not be correct.
\n" ); document.write( "you get a possible solution, but you still have to confirm that the possible solution is an actual solution by substituting that value for x in the original equation.
\n" ); document.write( "to summarize:
\n" ); document.write( "+/- 1 and +/- sqrt(15) were possible solutions to the original equation.
\n" ); document.write( "+/- 1 were the only solutions to the original equation.
\n" ); document.write( "that, to the best of my knowledge, is your answer.\r
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