document.write( "Question 498237: The width of a rectabgle is 1 meter more than half the length of the rectangle. If the perimeter of the rectangle is 40 meters, find the width and the length. I know A=w*l and P=2l+2w, however I can not figure out how to set this problem up.\r
\n" );
document.write( "\n" );
document.write( "Thank you,\r
\n" );
document.write( "\n" );
document.write( "Feona \n" );
document.write( "
Algebra.Com's Answer #336970 by cleomenius(959)![]() ![]() You can put this solution on YOUR website! length = x \n" ); document.write( "width = 1/2x + 1 \n" ); document.write( "2(x) + 2(1/2x + 1) = 40 \n" ); document.write( "This is the part I think you needed help with; setting up the equation. \n" ); document.write( "======================================================================= \n" ); document.write( "2x + x + 2 = 40 \n" ); document.write( "3x = 38 \n" ); document.write( "x = 12.7 meters = length \n" ); document.write( "7.35 meters = width \n" ); document.write( "2(12.7) + 2(6.35 + 1 ) = 40 meters. \n" ); document.write( "25.4 + 12.7 + 2 = 40.1 (round off error) \n" ); document.write( "Cleomenius.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |