document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498015>Question 498015</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a farmer has a rectangular garden plot surrounded by 200 ft of fence. Find the length and width of the garden if its area is 2400 ft squared </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336966 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336966\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> l*w = 2400<BR>\n" );
document.write( "Since we need 2 times the length and height to surround the area, we will use half of 200 for calculating the area.<BR>\n" );
document.write( "l= 100 - width<BR>\n" );
document.write( "w(100 -w) =  100w - w^2 = 2400<BR>\n" );
document.write( "100w - w^2 - 2400 = 0<BR>\n" );
document.write( "w^2 - 100w + 2400 = 0<BR>\n" );
document.write( "(x - 60) (x - 40)<BR>\n" );
document.write( "60 feet<BR>\n" );
document.write( "40 feet<BR>\n" );
document.write( "2(60) + 2(40) = 200 <BR>\n" );
document.write( "60 feet * 40 feet = 2400 feet.<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );