document.write( "Question 498213: Lisa has an average of 83 in her first four examinations. What should her average score be in the next two examinations be if she aims to have an average of 86?
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document.write( "the choices are:\r
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document.write( "the answer is 92 but i don't know how to solve for it \n" );
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Algebra.Com's Answer #336956 by htmentor(1343) You can put this solution on YOUR website! Lisa has an average of 83 in her first four examinations. What should her average score be in the next two examinations be if she aims to have an average of 86? \n" ); document.write( "================================= \n" ); document.write( "Let s1 = the 1st exam score, s2 = the 2nd score, etc. \n" ); document.write( "The average of the 1st four exams is computed from: \n" ); document.write( "(s1+s2+s3+s4)/4 = 83 -> s1+s2+s3+s4 = 332 \n" ); document.write( "The average of 86 for all six exams is computed from: \n" ); document.write( "(s1+s2+s3+s4+s5+s6)/6 = 86 -> s1+s2+s3+s4+s5+s6 = 516 \n" ); document.write( "Subtract the 1st equation from the 2nd: \n" ); document.write( "s5+s6 = 184 \n" ); document.write( "The average of the last two scores is (s5+s6)/2 = 184/2 = 92 \n" ); document.write( "Ans: 92 \n" ); document.write( " |