document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498138>Question 498138</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a field is 140 feet. The width is one-sixth of the length. Find the width of the field. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336935 by </B><A HREF=/tutors/aboutme.mpl?userid=Maths68><B>Maths68(1474)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Maths68><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Maths68><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336935\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Perimeter of a field = P = 140 feet<BR>\n" );
document.write( "Length  = L<BR>\n" );
document.write( "Width  = W=1/6(L)=L/6<BR>\n" );
document.write( "P = 2L + 2W<BR>\n" );
document.write( "Put values in above equation<BR>\n" );
document.write( "140=2L+2(L/6)<BR>\n" );
document.write( "140=2L+2L/6<BR>\n" );
document.write( "140=2L+L/3<BR>\n" );
document.write( "Multiply by 3 both sides<BR>\n" );
document.write( "420=6L+L<BR>\n" );
document.write( "420=7L<BR>\n" );
document.write( "420/7=L<BR>\n" );
document.write( "L=60<BR>\n" );
document.write( "Given<BR>\n" );
document.write( "W=L/6<BR>\n" );
document.write( "W=60/6<BR>\n" );
document.write( "W=6feet\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );