document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498148>Question 498148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> HELP!<BR>\n" );
document.write( "Find the equation of the straight line,<BR>\n" );
document.write( "trough (4,-2) and parallel with 2x+y-5 = 0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336919 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336919\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Trough or through?\r<BR>\n" );
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document.write( "Assuming \"through,\" we first find the slope of the given line, since the line we want will have the same slope. The given line is equivalent to y = -2x - 5, slope is -2. We can write the desired line in point-slope form.\r<BR>\n" );
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document.write( "y+2 = -2(x-4) </SPAN>\n" );
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