document.write( "Question 498038: I am having trouble setting up the following problem. I am not sure if the $43,750 is important in this question. \r
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document.write( "A bank has loaned out $500,000, part of it at 6% per annum and the rest of it at 11% per annum. If the bank receives $43,750 in interest each year, how much was loaned at 6%?\r
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Algebra.Com's Answer #336908 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A bank has loaned out $500,000, part of it at 6% per annum and the rest of it at 11% per annum. \n" ); document.write( "If the bank receives $43,750 in interest each year, how much was loaned at 6%? \n" ); document.write( ": \n" ); document.write( "Let x = amt loan out at 6% \n" ); document.write( "The total was given as $500000, therefore \n" ); document.write( "(500000-x) = amt loaned out at 11% \n" ); document.write( ": \n" ); document.write( "Write these as decimals \n" ); document.write( ": \n" ); document.write( "6% interest + 11% interest = total interest \n" ); document.write( ".06x + .11(500000-x) = 43750 \n" ); document.write( ".06x + 55000 - .11x = 43750 \n" ); document.write( ".06x - .11x = 43750 - 55000 \n" ); document.write( "-.05x = -11250 \n" ); document.write( "x = \n" ); document.write( "x = $225,000 loaned out 6% \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "You can confirm this by finding the amt loaned 11% (subtract 225000 from 500000) \n" ); document.write( "then finding the interest earned on the this, add to the above interest and confirm it total 43750 \n" ); document.write( " |