document.write( "Question 498038: I am having trouble setting up the following problem. I am not sure if the $43,750 is important in this question. \r
\n" ); document.write( "\n" ); document.write( "A bank has loaned out $500,000, part of it at 6% per annum and the rest of it at 11% per annum. If the bank receives $43,750 in interest each year, how much was loaned at 6%?\r
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Algebra.Com's Answer #336908 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
A bank has loaned out $500,000, part of it at 6% per annum and the rest of it at 11% per annum.
\n" ); document.write( "If the bank receives $43,750 in interest each year, how much was loaned at 6%?
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\n" ); document.write( "Let x = amt loan out at 6%
\n" ); document.write( "The total was given as $500000, therefore
\n" ); document.write( "(500000-x) = amt loaned out at 11%
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\n" ); document.write( "Write these as decimals
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\n" ); document.write( "6% interest + 11% interest = total interest
\n" ); document.write( ".06x + .11(500000-x) = 43750
\n" ); document.write( ".06x + 55000 - .11x = 43750
\n" ); document.write( ".06x - .11x = 43750 - 55000
\n" ); document.write( "-.05x = -11250
\n" ); document.write( "x = \"%28-11250%29%2F%28-.05%29\"
\n" ); document.write( "x = $225,000 loaned out 6%
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\n" ); document.write( "You can confirm this by finding the amt loaned 11% (subtract 225000 from 500000)
\n" ); document.write( "then finding the interest earned on the this, add to the above interest and confirm it total 43750
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