document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=497817>Question 497817</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the altitude of a triangle where all sides equal 1 inch?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336903 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This would be an equilateral triangle, when you drop an altitude from one vertex to the opposite base you are forming a 30 -60 -90 tringle.<BR>\n" );
document.write( "If we let s represent the side, the formula to find the side opposite the 60 degree angle, which is what you are looking for, will be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >/2 * s.<BR>\n" );
document.write( "So if s = one inch, the altitude will be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%283%29 ALIGN=MIDDLE  ALT=\"sqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >/2  inches.<BR>\n" );
document.write( "Cleomenius. </SPAN>\n" );
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