document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498059>Question 498059</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a triangle, the measure of the first angle is 3 times the measure of the 2nd angle. The measure of the third angle is 45 degrees more than the measure of the second angle. use the fact that the sum of the measures of the three angles of a triangle is 180 degrees to find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336900 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336900\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = 3x<BR>\n" );
document.write( "B = x<BR>\n" );
document.write( "C = x + 45<BR>\n" );
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document.write( "3x + x + x + 45 = 180.<BR>\n" );
document.write( "5x + 45 = 180<BR>\n" );
document.write( "5x = 135<BR>\n" );
document.write( "x = 27<BR>\n" );
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document.write( "A = 3(27) = 81 degrees<BR>\n" );
document.write( "B = 27 degrees<BR>\n" );
document.write( "C = 27 + 45 = 72 degrees.<BR>\n" );
document.write( "72 + 27 + 81 = 180 degrees.<BR>\n" );
document.write( "This does check.<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );