document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=497906>Question 497906</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of one angle of a triangle is twice the measure of a second angle. The measure of the third angle is 12 less than the sum of the other two. Find the measures of the angles of the triangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336895 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336895\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = 2x<BR>\n" );
document.write( "B = x<BR>\n" );
document.write( "C = x + 2x - 12<BR>\n" );
document.write( "===========================================<BR>\n" );
document.write( "2x + x + x + 2x -12 = 180 degrees.<BR>\n" );
document.write( "6x = 12 = 180 degrees<BR>\n" );
document.write( "6x =192<BR>\n" );
document.write( "x = 28<BR>\n" );
document.write( "============================================<BR>\n" );
document.write( "A = 64 degrees<BR>\n" );
document.write( "B = 32 degrees<BR>\n" );
document.write( "C = 84 degrees<BR>\n" );
document.write( "==========================================<BR>\n" );
document.write( "64 + 32 + 84 = 180 degrees. This does check.<BR>\n" );
document.write( "Cleomenius.\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );