document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=497984>Question 497984</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The shortest side of a triangle is 5 inches less than the medium  side. The larger size is 12 inches more than the medium size side. If the perimeter is 40 inches, find the size of each side of a triangle.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336894 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336894\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A = x - 5<BR>\n" );
document.write( "B = x <BR>\n" );
document.write( "C = x + 12<BR>\n" );
document.write( "x - 5 + x + x + 12 = 180<BR>\n" );
document.write( "3x + 7 = 180<BR>\n" );
document.write( "3x = 173.<BR>\n" );
document.write( "B = 57.7 degrees<BR>\n" );
document.write( "A = 52.7 degrees<BR>\n" );
document.write( "C = 69.7 degrees<BR>\n" );
document.write( "57.7 + 52.7 + 69.7 = 180.1 degrees, approx 180 degrees with a round off error.<BR>\n" );
document.write( "Cleomenius.\r<BR>\n" );
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