document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=498003>Question 498003</A>: <I><SPAN STYLE=\"word-break: break-all;\"> on his way to visit Soren, Peter averaged 7 mi/h on his skateboard and 4 mi/h walking.  If Soren lives 6 mi away and the whole trip took 1 hr, how many miles did Peter travel by skateboard? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336893 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336893\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This example is similar:<BR>\n" );
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document.write( "You can jog at a speed of 8 miles per hour, and run at a speed of 12 miles per hour.  If you traveled 6 miles in 40 minutes, find the amount of time you jogged as well as the amount of time you ran.<BR>\n" );
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document.write( "40 minutes = 2/3 hours<BR>\n" );
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document.write( "d = distance jogging<BR>\n" );
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document.write( "d/8 + (6-d)/12 = 2/3 hours<BR>\n" );
document.write( "times 48<BR>\n" );
document.write( "6d + 4(6-d) = 32<BR>\n" );
document.write( "2d + 24 = 32<BR>\n" );
document.write( "2d = 8<BR>\n" );
document.write( "d = 4 miles jogging<BR>\n" );
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document.write( "2 miles running<BR>\n" );
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