document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=497324>Question 497324</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If m&#8736;BGC=16x-4 and m&#8736;CGD=2x+13, find the calue of x so that &#8736;BGD is a right angle.   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336781 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336781\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 16x - 4 + 2x + 13 = 90 degrees.<BR>\n" );
document.write( "18x + 9 = 90 degrees.<BR>\n" );
document.write( "18x = 81<BR>\n" );
document.write( "x = 4.5<BR>\n" );
document.write( "16(4.5) - 4 = 68 degrees.<BR>\n" );
document.write( "2(4.5) + 13 = 22 degrees.  <BR>\n" );
document.write( "68 + 22 = 90 degrees. This does check.<BR>\n" );
document.write( "Cleomenius.<BR>\n" );
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