document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=497557>Question 497557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at 900am two people leave their homes that are 15 miles apart walking toward each other. if one person walks at a rate 4mph faster than the other and they meet after 1.5 hours, how fast was each person walking? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336759 by </B><A HREF=/tutors/aboutme.mpl?userid=htmentor><B>htmentor(1343)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=htmentor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=htmentor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336759\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let d = the distance traveled by the slower person<BR>\n" );
document.write( "Then 15 - d = the distance traveled by the faster person<BR>\n" );
document.write( "Let s = the slower person's speed<BR>\n" );
document.write( "Then s + 4 = the faster person's speed<BR>\n" );
document.write( "Since speed = distance/time, and the time is 1.5 h, the slower person's speed is:<BR>\n" );
document.write( "s = d/1.5 [1]<BR>\n" );
document.write( "And the faster person's speed is:<BR>\n" );
document.write( "s + 4 = (15 - d)/1.5 [2]<BR>\n" );
document.write( "Solve for s in [1] and substitute into [2]:<BR>\n" );
document.write( "s + 4 = (15 - 1.5s)/1.5<BR>\n" );
document.write( "s + 4 = 10 - s<BR>\n" );
document.write( "2s = 6<BR>\n" );
document.write( "s = 3<BR>\n" );
document.write( "Therefore, their speeds are 3 mph and 7 mph </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );