document.write( "Question 497590: going down the river a boat went 10mph. going up the river it only went 2mph. find the current and the speed of the boat if there were no current. \n" ); document.write( "
Algebra.Com's Answer #336757 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"c\" = the speed of the current
\n" ); document.write( "Let \"+b\" = the speed of the boat in still water
\n" ); document.write( "Going downriver, the boat travels at \"+b+%2B+c+\" mi/hr
\n" ); document.write( "Going upriver, the boat travels at \"+b+-+c+\" mi/hr
\n" ); document.write( "-----------------
\n" ); document.write( "given:
\n" ); document.write( "going downriver,
\n" ); document.write( "(1) \"+b+%2B+c+=+10+\" mi/hr
\n" ); document.write( "going upriver,,
\n" ); document.write( "(2) \"+b+-+c+=+2+\" mi/hr
\n" ); document.write( "-----------------
\n" ); document.write( "(1) \"+c+=+10+-+b+\"
\n" ); document.write( "Substitute this into (2)
\n" ); document.write( "(2) \"+b+-+%28+10+-+b+%29+=+2+\"
\n" ); document.write( "(2) \"+b+-+10+%2B+b+=+2+\"
\n" ); document.write( "(2) \"+2b+=+12+\"
\n" ); document.write( "(2) \"+b+=+6+\"
\n" ); document.write( "The speed of the boat if there is no current is 6 mi/hr
\n" ); document.write( "
\n" );