document.write( "Question 497536: Shanika has invested in 3 different stocks. Stock A is currently worth $4.50 per share. Stock B is worth $7.00 per share, while stock C is worth $10.00 per share. Shanika purchased half as many shares of stock B as stock A and half as many shares of stock C as stock B. If her total investments are currently worth %546, how many shares of each stock does she own? \n" ); document.write( "
Algebra.Com's Answer #336750 by mananth(16946)![]() ![]() You can put this solution on YOUR website! Stock A = x-----------------4.50 \n" ); document.write( "Stock B = x/2---------------7.00 \n" ); document.write( "Stock C = x/4---------------10.00\r \n" ); document.write( "\n" ); document.write( "Total investment = 546\r \n" ); document.write( "\n" ); document.write( "4.5x+7*(x/2)+10*(x/4)=546\r \n" ); document.write( "\n" ); document.write( "multiply by 4\r \n" ); document.write( "\n" ); document.write( "18x+14x+10x=2184 \n" ); document.write( "42x=2184 \n" ); document.write( "x=52 ----------- A \n" ); document.write( "26----------------B \n" ); document.write( "13----------------C \n" ); document.write( "CHECK\r \n" ); document.write( "\n" ); document.write( "52*4.5+26*7+13*10=546\r \n" ); document.write( "\n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |