document.write( "Question 497522: how much of a 60% orange juice drink must be mixed with 4 gallons of a 30% orange juice drink to obtain a mixture of 50% orange juice? \n" ); document.write( "
Algebra.Com's Answer #336743 by mananth(16946)![]() ![]() You can put this solution on YOUR website! percent ---------------- quantity \n" ); document.write( "Orange juice I 30 ---------------- 4 gallons \n" ); document.write( "Orange juice II 60 ---------------- x gallons \n" ); document.write( "Mixture 50 ---------------- 4 + x gallons \n" ); document.write( " \n" ); document.write( "30 * 4 + 60 x = 50 ( 4 + x ) \n" ); document.write( "120 + 60 x = 200 + 50 x \n" ); document.write( "60 x + -50 x = 200 - -120 \n" ); document.write( "10 x = 80 \n" ); document.write( "/ 10 \n" ); document.write( "x = 8 \n" ); document.write( " 8 gallons of 60 % Orange juice II II \n" ); document.write( " \n" ); document.write( " |