document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=497518>Question 497518</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A bird travels at 500 mph and leaves 10 minutes before his bird friend, which travels at 1500 mphs. How long does it take the friend bird to catch up to the bird that left 10 minutes before him? ... ANSWER NOW IM CURRENTLY IN MY MATH CLASS AND IN BIG TROUBLE IF YOU DONT ANSWER THIS!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336742 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336742\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Bird I 500 mph<BR>\n" );
document.write( "Bird II 1500 mph\r<BR>\n" );
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document.write( "In 10 minutes = 1/6 hour bird I travels 500*1/6 = 83.33 miles.\r<BR>\n" );
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document.write( "difference between their speeds = 1000 \r<BR>\n" );
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document.write( "d= 83.33<BR>\n" );
document.write( "speed = 1000 mph\r<BR>\n" );
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document.write( "time = d/r<BR>\n" );
document.write( "83.33/1000 <BR>\n" );
document.write( "0.0833 hours<BR>\n" );
document.write( "0.0833*3600= 300 seconds\r<BR>\n" );
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document.write( "time to catchup = 300 seconds </SPAN>\n" );
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