document.write( "Question 497438: how do i solve
\n" ); document.write( "the square root of 3x-3 minus the square root of x plus 5 = 6
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Algebra.Com's Answer #336731 by lwsshak3(11628)\"\" \"About 
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how do i solve
\n" ); document.write( "the square root of 3x-3 minus the square root of x plus 5 = 6
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\n" ); document.write( "√(3x-3)-√(x+5)=6
\n" ); document.write( "isolate one of the radicals
\n" ); document.write( "√(3x-3)=6+√(x+5)
\n" ); document.write( "square both sides
\n" ); document.write( "3x-3=36+12√(x+5)+x+5
\n" ); document.write( "isolate radical
\n" ); document.write( "12√(x+5)=2x-44
\n" ); document.write( "square both sides
\n" ); document.write( "144(x+5)=4x^2-176x+1936
\n" ); document.write( "144x+720=4x^2-176x+1936
\n" ); document.write( "4x^2-320x+1216=0
\n" ); document.write( "x^2-80x+304=0
\n" ); document.write( "use quadratic formula or factor
\n" ); document.write( "(x-4((x-76)=0
\n" ); document.write( "x=4
\n" ); document.write( "or
\n" ); document.write( "x=76
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