document.write( "Question 497241: please help me solve this problem: log3(0.1)+2log3(x)= log3(2)+log3(5) \n" ); document.write( "
Algebra.Com's Answer #336708 by Earlsdon(6294)\"\" \"About 
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\"Log%5B3%5D%280.1%29%2B2%2ALog%5B3%5D%28x%29+=+Log%5B3%5D%282%29%2BLog%5B3%5D%285%29\" Apply the \"product rule\" for logarithms: \"Log%5Bb%5D%28M%29%2BLog%5Bb%5D%28N%29+=+Log%5Bb%5D%28M%2AN%29\" and the \"power rule\": \"p%2ALog%5Bb%5D%28M%29+=+Log%5Bb%5D%28M%5Ep%29\"
\n" ); document.write( "\"Log%5B3%5D%280.1x%5E2%29+=+Log%5B3%5D%282%2A5%29\" but...If \"Log%5Bb%5D%28x%29+=+Log%5Bb%5D%28y%29\" then \"x+=+y\" so...
\n" ); document.write( "\"0.1x%5E2+=+2%2A5\"
\n" ); document.write( "\"x%5E2+=+10%2F0.1\"
\n" ); document.write( "\"x%5E2+=+100\"
\n" ); document.write( "\"x+=+10\"
\n" ); document.write( "
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