document.write( "Question 497136: \r
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\n" ); document.write( "\n" ); document.write( " Jack and Jill went up the hill at a rate of 8 units per minute. They came tumbling down at a rate of 8 units per second. What was their average rate , in units oer minute, for the round trip?\r
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Algebra.Com's Answer #336685 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Jack and Jill went up the hill at a rate of 8 units per minute.
\n" ); document.write( "They came tumbling down at a rate of 8 units per second.
\n" ); document.write( " What was their average rate, in units per minute, for the round trip?
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\n" ); document.write( "Find the tumbling down rate in units/min
\n" ); document.write( "8*60 = 480 units per minute
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\n" ); document.write( "Let d = the one-way distance
\n" ); document.write( "Let a = average units/min for the round trip (2d)
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\n" ); document.write( "Write a time equation; time = dist/rate
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\n" ); document.write( "Up time + tumble down time = total time
\n" ); document.write( "\"d%2F8\" + \"d%2F480\" = \"%282d%29%2Fa\"
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\n" ); document.write( "multiply by 480a, results
\n" ); document.write( "60ad + ad = 960d
\n" ); document.write( "61ad = 960d
\n" ); document.write( "we don't care about d, divide thru by d, to eliminate it.
\n" ); document.write( " 61a = 960
\n" ); document.write( "a = \"960%2F61\"
\n" ); document.write( "a = 15.738 units/minute average rate
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\n" ); document.write( "Confirm this, let the one way dist = 1, find the times
\n" ); document.write( "\"1%2F8\" + \"1%2F480%29\" = \"2%2F15.738%29\"
\n" ); document.write( "use decimals here
\n" ); document.write( ".125 + .002 = .127, confirms our average speed of 15.738 units/min
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