document.write( "Question 497045: you have 100 feet of fencing for a garden to be built along the long wall at the back of your yard. what are the dimensions of the largest garden that can be enclosed by this fencing? \n" ); document.write( "
Algebra.Com's Answer #336664 by cleomenius(959)\"\" \"About 
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The perimeter of the rectangle is
\n" ); document.write( "2W + 2 L
\n" ); document.write( "Because there are only 3 sides, the perimeter will be
\n" ); document.write( "P = 2W + L\r
\n" ); document.write( "\n" ); document.write( "100 = 2W + L\r
\n" ); document.write( "\n" ); document.write( "Now, rearrange for length
\n" ); document.write( "L = 100 = 2W\r
\n" ); document.write( "\n" ); document.write( "Now the area formula:
\n" ); document.write( "A = L*W
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\n" ); document.write( "Area = W(100 - 2W)
\n" ); document.write( "Area = 100x -2x^2
\n" ); document.write( "This becomes a quadratic equation:
\n" ); document.write( "-2W^2 + 100W
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\n" ); document.write( "Find the max area width by finding the axis of symmetry;
\n" ); document.write( "W = -b/(2a)
\n" ); document.write( "a= -2
\n" ); document.write( "b = 100\r
\n" ); document.write( "\n" ); document.write( "W = -100 / -4
\n" ); document.write( "W = 25 feet. This is the width.\r
\n" ); document.write( "\n" ); document.write( "L = 100 - 2W = 50 feet. This is the length.
\n" ); document.write( "25 * 50 = 1250 ft, this is the maximum area.
\n" ); document.write( "Cleomenius.\r
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