document.write( "Question 496643: The square of the differene between a number and 12 is twice the number.
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document.write( "what is the number? \n" );
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Algebra.Com's Answer #336519 by bucky(2189) ![]() You can put this solution on YOUR website! Let x be the unknown number. Then the difference between the unknown number and 12 can be written as \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Squaring out the left side makes the equation become: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Subtract 2x from both sides to get the equation into the more conventional quadratic form having zero on the right side: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "This quadratic equation can be solved by factoring the left side as follows: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "And this equation will be true if either of the factors is zero because a multiplication on the left side by a zero factor makes the left side equal to the right side. So either: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "or: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "If you didn't recognize the factoring, you could always use the quadratic formula to solve the quadratic equation. Recognize that the quadratic equation that we developed is in the form: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and by comparing this form to the equation we developed, you can see that a = 1, b = -26, and c = 144. Substitute these values into the quadratic formula as follows: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Within the radical sign, square the -26 and multiply out the -4*1*144 to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and the terms in the radical become 100. Taking the square root of the 100 reduces the formula to: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Remove the parentheses around the -26 and also multiply out the denominator to get: \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "and this becomes either \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( "Check: Does \n" ); document.write( ". \n" ); document.write( "Also check: Does \n" ); document.write( ". \n" ); document.write( "The two answers to this problem that will satisfy the requirements are x = 18 and x = 8. \n" ); document.write( ". \n" ); document.write( "Hope this helps you understand how to go about working this problem. \n" ); document.write( " |