document.write( "Question 496643: The square of the differene between a number and 12 is twice the number.
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Algebra.Com's Answer #336519 by bucky(2189)\"\" \"About 
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Let x be the unknown number. Then the difference between the unknown number and 12 can be written as \"x+-+12\". This quantity is to be squared and it is to equal two times the unknown number. In equation form this becomes:
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\n" ); document.write( "\"%28x-12%29%5E2+=+2x\"
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\n" ); document.write( "Squaring out the left side makes the equation become:
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\n" ); document.write( "\"x%5E2+-+24x+%2B+144+=+2x\"
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\n" ); document.write( "Subtract 2x from both sides to get the equation into the more conventional quadratic form having zero on the right side:
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\n" ); document.write( "\"x%5E2+-+26x+%2B+144+=+0\"
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\n" ); document.write( "This quadratic equation can be solved by factoring the left side as follows:
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\n" ); document.write( "\"%28x+-+18%29%2A%28x+-+8%29+=+0\"
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\n" ); document.write( "And this equation will be true if either of the factors is zero because a multiplication on the left side by a zero factor makes the left side equal to the right side. So either:
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\n" ); document.write( "\"x+-+18+=+0+\" which by adding 18 to both sides becomes \"x+=+18\"
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\n" ); document.write( "or:
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\n" ); document.write( "\"x+-+8+=+0\" which by adding 8 to both sides becomes \"x+=+8\"
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\n" ); document.write( "If you didn't recognize the factoring, you could always use the quadratic formula to solve the quadratic equation. Recognize that the quadratic equation that we developed is in the form:
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\n" ); document.write( "\"ax%5E2+%2B+bx+%2B+c+=+0\"
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\n" ); document.write( "and by comparing this form to the equation we developed, you can see that a = 1, b = -26, and c = 144. Substitute these values into the quadratic formula as follows:
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\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
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\n" ); document.write( "\"x+=+%28-%28-26%29+%2B-+sqrt%28+%28-26%29%5E2-4%2A1%2A144+%29%29%2F%282%2A1%29+\"
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\n" ); document.write( "Within the radical sign, square the -26 and multiply out the -4*1*144 to get:
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\n" ); document.write( "\"x+=+%28-%28-26%29+%2B-+sqrt%28+676-576+%29%29%2F%282%2A1%29+\"
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\n" ); document.write( "and the terms in the radical become 100. Taking the square root of the 100 reduces the formula to:
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\n" ); document.write( "\"x+=+%28-%28-26%29+%2B-+10%29%2F%282%2A1%29+\"
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\n" ); document.write( "Remove the parentheses around the -26 and also multiply out the denominator to get:
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\n" ); document.write( "\"x+=+%2826+%2B-+10%29%2F2+\"
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\n" ); document.write( "and this becomes either \"x+=+%2826%2B10%29%2F2+\" or \"x+=+%2826-10%29%2F2\" and from these we again get the answers:
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\n" ); document.write( "\"x+=+18\" and \"x+=+8\"
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\n" ); document.write( "Check: Does \"%2818+-+12%29%5E2\" equal \"2%2A18\"? If you work this out you get \"36+=+36\" so it does work.
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\n" ); document.write( "Also check: Does \"+%288+-+12%29%5E2+\" equal \"2%2A8\"? If you work this out you find that \"%28-4%29%5E2+=+16\" are equal and so this solution also works.
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\n" ); document.write( "The two answers to this problem that will satisfy the requirements are x = 18 and x = 8.
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\n" ); document.write( "Hope this helps you understand how to go about working this problem.
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