document.write( "Question 496228: How do I use logarithms to solve
\n" ); document.write( "10(1.07^5x+1)=12 \n" ); document.write( "
Algebra.Com's Answer #336513 by lwsshak3(11628)\"\" \"About 
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How do I use logarithms to solve
\n" ); document.write( "10(1.07^(5x+1)=12
\n" ); document.write( "(1.07^(5x+1)=12/10=1.2
\n" ); document.write( "take log of both sides
\n" ); document.write( "(5x+1)log(1.07)=log(1.2)
\n" ); document.write( "5x+1=log1.2/log1.07=2.6947
\n" ); document.write( "5x=2.6947-1=1.6947
\n" ); document.write( "x=1.6947/5=.3389
\n" ); document.write( "Check:
\n" ); document.write( "10(1.07^(5x+1)
\n" ); document.write( "10(1.07^(2.6947)=10*1.2=12\r
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