document.write( "Question 496656: A can do a piece of work in 10 days. After he has worked 2 days, B came to help him and together they finished it in 3 days. In how many days could B alone have done the work? Please give an answer. Thank you \n" ); document.write( "
Algebra.Com's Answer #336511 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! In work problems, you add their rates of \n" ); document.write( "working to get their rate working together. \n" ); document.write( "A's rate is ( 1 job ) / ( 10 days ) = \n" ); document.write( "B's rate is ( 1 job ) / ( x days ) = \n" ); document.write( "----------------------- \n" ); document.write( "The question to ask is: \" What part of the job \n" ); document.write( "does A get done in 2 days?\" \n" ); document.write( "If he does 1 job in 10 days, he does 1/10 \n" ); document.write( "of a job in 1 day. That means he does 2/10 \n" ); document.write( "or 1/5 of a job in 2 days. \n" ); document.write( "----------------------- \n" ); document.write( "So, there is \n" ); document.write( "to do when B joins him \n" ); document.write( "So, they do 4/5 of the job together in 3 days \n" ); document.write( "----------------------- \n" ); document.write( "Adding their rates of working: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Multiply both sides by \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "B alone could have done the work in 6 hours \n" ); document.write( " |