document.write( "Question 496656: A can do a piece of work in 10 days. After he has worked 2 days, B came to help him and together they finished it in 3 days. In how many days could B alone have done the work? Please give an answer. Thank you \n" ); document.write( "
Algebra.Com's Answer #336511 by josmiceli(19441)\"\" \"About 
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In work problems, you add their rates of
\n" ); document.write( "working to get their rate working together.
\n" ); document.write( "A's rate is ( 1 job ) / ( 10 days ) = \"+1%2F10+\"
\n" ); document.write( "B's rate is ( 1 job ) / ( x days ) = \"+1%2Fx+\"
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\n" ); document.write( "The question to ask is: \" What part of the job
\n" ); document.write( "does A get done in 2 days?\"
\n" ); document.write( "If he does 1 job in 10 days, he does 1/10
\n" ); document.write( "of a job in 1 day. That means he does 2/10
\n" ); document.write( "or 1/5 of a job in 2 days.
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\n" ); document.write( "So, there is \"+1+-+1%2F5+=+4%2F5+\" of the job left
\n" ); document.write( "to do when B joins him
\n" ); document.write( "So, they do 4/5 of the job together in 3 days
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\n" ); document.write( "Adding their rates of working:
\n" ); document.write( "\"+1%2F10+%2B+1%2Fx+=+%284%2F5%29%2F3+\"
\n" ); document.write( "\"+1%2F10+%2B+1%2Fx+=+4%2F15+\"
\n" ); document.write( "Multiply both sides by \"+30x+\"
\n" ); document.write( "\"+3x+%2B+30+=+8x+\"
\n" ); document.write( "\"+5x+=+30+\"
\n" ); document.write( "\"+x+=+6+\"
\n" ); document.write( "B alone could have done the work in 6 hours
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