document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=496132>Question 496132</A>: <I><SPAN STYLE=\"word-break: break-all;\"> PLEASE HELP....THE NUMBERS ON KARL'S THREE RAFFLE TICKETS ARE CONSECUTIVE INTEGERS. THE SUM OF THE NUMBERS IS 138.WHAT ARE THE NUMBERS? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336436 by </B><A HREF=/tutors/aboutme.mpl?userid=rabrox><B>rabrox(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rabrox><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336436\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, you would add all of the x's together. The coeffiecient of each x is 1.<BR>\n" );
document.write( "So: 1x + 1x + 1x= 3x.<BR>\n" );
document.write( "Then you would add the numbers.<BR>\n" );
document.write( "1+2= 3<BR>\n" );
document.write( "So now you have 3x+3=138. Next, you subrtract the 3 from each side of the equation. You should end up with 3x= 135. To solve for x, you divide each side of the equation by 3. So x=45<BR>\n" );
document.write( "So the numbers are:<BR>\n" );
document.write( "45,46, and 47 </SPAN>\n" );
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