document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=50575>Question 50575</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The measure of a supplement of an angle is 12 degrees greater than three times the measure of a complement. Find the measure of the angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #33641 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=33641\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> supplement = 180-x<BR>\n" );
document.write( "complement = 90-x<BR>\n" );
document.write( "EQUATION:<BR>\n" );
document.write( "180-x=12+3(90-x)<BR>\n" );
document.write( "180-x=12+270-3x<BR>\n" );
document.write( "2x=102<BR>\n" );
document.write( "x=51<BR>\n" );
document.write( "Hence, the measure of the angle is 51 degrees<BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );