document.write( "Question 496162: You invested $7000 in two accounts paying 8% and 6% annual interest, respectively. If the total interest earned for the year was $448, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #336392 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! .08n+.06(7000-n)=448 \n" ); document.write( "8n+6(7000-n)=44800 \n" ); document.write( "8n+42000-6n=44800 \n" ); document.write( "2n=2800 \n" ); document.write( "n=1400 \n" ); document.write( "7000-n=5600 \n" ); document.write( "$1400 was invested at 8%, and $5600 was invested at 6%.. \n" ); document.write( " |