document.write( "Question 495649: A flagpole 40 ft high stands on top of the Wentworth Building. From a point P in the front of Bailey's Drugstore, the angle of elevation of the top of the pole is 54.9°, and the angles of elevation of the bottom of the pole is 47.5° Find the height of the Wentworth Building. \n" ); document.write( "
Algebra.Com's Answer #336386 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! A flagpole 40 ft high stands on top of the Wentworth Building. From a point P in the front of Bailey's Drugstore, the angle of elevation of the top of the pole is 54.9°, and the angles of elevation of the bottom of the pole is 47.5° Find the height of the Wentworth Building. \n" ); document.write( "** \n" ); document.write( "Draw a right triangle with the vertical leg=40+x, x representing the difference in height between the Baily Drugstore and Wentworth Bldg, and a horizontal leg=y representing the distance betweeen the two bldgs. You now have two right triangles to work with: \n" ); document.write( "tan 54.9º=(40+x)/y \n" ); document.write( "tan 47.5º=x/y \n" ); document.write( "Height of Wentworth Bldg=40+x \n" ); document.write( ".. \n" ); document.write( "tan 47.5=x/y \n" ); document.write( "y=x/tan 47.5º \n" ); document.write( "sub y in first equation \n" ); document.write( "tan 54.9º=(40+x)/(x/tan 47.5º \n" ); document.write( "(40+x)/x=tan 54.9º/tan 47.5)=1.3038 \n" ); document.write( "40+x=1.3038x \n" ); document.write( "1.3038x-x=40 \n" ); document.write( ".3038x=40 \n" ); document.write( "x=40/.3038=131 ft \n" ); document.write( "40+x=131+40=171 ft \n" ); document.write( "Ans: \n" ); document.write( "Height of Wentworth Bldg=171 ft \n" ); document.write( " |