document.write( "Question 495722: the perimeter of a rectangle is 54m. the length is 6m then twice the width. what is the dimentions \n" ); document.write( "
Algebra.Com's Answer #336385 by cleomenius(959)\"\" \"About 
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W = x
\n" ); document.write( "L = 2x + 6 \r
\n" ); document.write( "\n" ); document.write( "2x + 4x + 12 = 54
\n" ); document.write( "6x = 42
\n" ); document.write( "x = 7 m, this is the width.
\n" ); document.write( "14 + 6 = 20 m, this is the length.
\n" ); document.write( "2(7) + 2(20) = 54 m.
\n" ); document.write( "This does check.
\n" ); document.write( "Cleomenius.\r
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