document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=496130>Question 496130</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two children own two-way radios that have a maximum range of 4 miles. One leaves a certain point at 1:00 P.M., walking due north at a rate of 4 mi/hr. The other leaves the same point at 1:15 P.M., traveling due south at 6 mi/hr. When will they be unable to communicate with one another? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336373 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336373\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4 mi/hr x 1/4 hour = 1 mile<BR>\n" );
document.write( "n(4+6)=3<BR>\n" );
document.write( "10n=3<BR>\n" );
document.write( "n=3/10 x 60 min/hr=18 mins<BR>\n" );
document.write( "1:15 + 18 mins=1:33 p.m. is when they will last be able to communicate with each other.. </SPAN>\n" );
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