document.write( "Question 496065: solve for x and y ; if x>0 and y>0 : log xy=log x/y + 2 log 2= 2 \n" ); document.write( "
Algebra.Com's Answer #336316 by chessace(471)![]() ![]() You can put this solution on YOUR website! log x + log y = 2 \n" ); document.write( "log x - log y + 2 log 2 = 2 \n" ); document.write( "2 log y - 2 log 2 = 0 \n" ); document.write( "y = 2 \n" ); document.write( "log 2x = 2 \n" ); document.write( "2x = 100 \n" ); document.write( "x = 50 \n" ); document.write( " \n" ); document.write( " |