document.write( "Question 496065: solve for x and y ; if x>0 and y>0 : log xy=log x/y + 2 log 2= 2 \n" ); document.write( "
Algebra.Com's Answer #336316 by chessace(471)\"\" \"About 
You can put this solution on YOUR website!
log x + log y = 2
\n" ); document.write( "log x - log y + 2 log 2 = 2
\n" ); document.write( "2 log y - 2 log 2 = 0
\n" ); document.write( "y = 2
\n" ); document.write( "log 2x = 2
\n" ); document.write( "2x = 100
\n" ); document.write( "x = 50
\n" ); document.write( "
\n" ); document.write( "
\n" );