document.write( "Question 495922: A train leaves Miami at 1:00p.m. The second train leaves the same city in the same direction at 6:00p.m. The second train travels 105mph faster than the first. If the second overtakes the first at 9:00p.m. what is the speed of each of the two trains? \n" ); document.write( "
Algebra.Com's Answer #336309 by ankor@dixie-net.com(22740)\"\" \"About 
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A train leaves Miami at 1:00p.m.
\n" ); document.write( "The second train leaves the same city in the same direction at 6:00p.m.
\n" ); document.write( " The second train travels 105mph faster than the first.
\n" ); document.write( "If the second overtakes the first at 9:00p.m.
\n" ); document.write( "what is the speed of each of the two trains?
\n" ); document.write( ":
\n" ); document.write( "From the above information, we know:
\n" ); document.write( "The 2nd train overtakes the 1st train in 3 hrs
\n" ); document.write( "The travel time of the 1st train will be 8 hrs, when it's overtaken
\n" ); document.write( ":
\n" ); document.write( "Let s = speed of the 1st train
\n" ); document.write( "then
\n" ); document.write( "(s+105) = speed of the 2nd train
\n" ); document.write( ":
\n" ); document.write( "When 2nd train overtakes the 1st, they will have traveled the same distance
\n" ); document.write( "Write a distance equation; dist = speed * time
\n" ); document.write( ":
\n" ); document.write( "8s = 3(s+105)
\n" ); document.write( "8s = 3s + 315
\n" ); document.write( "8s - 3s = 315
\n" ); document.write( "5s = 315
\n" ); document.write( "s = \"315%2F5\"
\n" ); document.write( "s = 63 mph is the speed of the 1st train
\n" ); document.write( "and
\n" ); document.write( "63 + 105 = 168 mph is the speed of the 2nd train
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this by finding the distance each travel; they should be equal
\n" ); document.write( "63*8 = 504 mi
\n" ); document.write( "168*3 = 504 mi \n" ); document.write( "
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