document.write( "Question 495931: Car \"A\" is travelling at a speed of 40MPH.
\n" ); document.write( "Car \"B\" is 170 yards in front.
\n" ); document.write( "Both cars travel for 530 yards and during that time car \"A\" reaches speeds of 70MPH to catch upto car \"B\".
\n" ); document.write( "What speed is car \"B\" travelling at?
\n" ); document.write( "

Algebra.Com's Answer #336307 by ankor@dixie-net.com(22740)\"\" \"About 
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Car \"A\" is traveling at a speed of 40MPH.
\n" ); document.write( "Car \"B\" is 170 yards in front.
\n" ); document.write( "Both cars travel for 530 yards and during that time car \"A\" reaches speeds of 70MPH to catch up to car \"B\".
\n" ); document.write( "What speed is car \"B\" traveling at?
\n" ); document.write( ":
\n" ); document.write( "What bothers me about this problem is that it says both cars travel 530 yds
\n" ); document.write( "Obviously for Car A to catch up with car B, it will have travel further than B
\n" ); document.write( ":
\n" ); document.write( "When A catches B
\n" ); document.write( "Car B travels 530 yds
\n" ); document.write( "Car A travels 530 + 170 = 700 yds
\n" ); document.write( ":
\n" ); document.write( "Find the average velocity of Car A that uniformly accelerates from 40 to 70 mph
\n" ); document.write( "Av = \"%28%2870%2B40%29%29%2F2\"
\n" ); document.write( "Av = 55 mph
\n" ); document.write( ":
\n" ); document.write( "Let s = speed of car B
\n" ); document.write( ":
\n" ); document.write( "\"s%2F55\" = \"530%2F700\"
\n" ); document.write( "700s = 55 * 530
\n" ); document.write( "700s = 29150
\n" ); document.write( "s = \"29150%2F700\"
\n" ); document.write( "s = 41.643 mph is Car B's speed
\n" ); document.write( "
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