document.write( "Question 496042: Solve using the substitution method
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document.write( "1/3 x - 1/5 y = 7
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document.write( "1/6 x + 2/5 y = -4\r
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document.write( "Not sure how to work substitution method using fractions.
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document.write( "Need to find answer for both variables seperately. \n" );
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Algebra.Com's Answer #336306 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! Solve using the substitution method \n" ); document.write( "1/3 x - 1/5 y = 7 \n" ); document.write( "1/6 x + 2/5 y = -4 \n" ); document.write( "----------------- \n" ); document.write( "Then eliminate the fractions and go from there. \n" ); document.write( "1/3 x - 1/5 y = 7 \n" ); document.write( "times 15 --> 5x - 3y = 105 \n" ); document.write( "----------------- \n" ); document.write( "1/6 x + 2/5 y = -4 \n" ); document.write( "times 30 --> 5x + 12y = -120 \n" ); document.write( "------------ \n" ); document.write( "5x - 3y = 105 --> 5x = 3y + 105 \n" ); document.write( "5x + 12y = -120 \n" ); document.write( "------------- \n" ); document.write( "Sub for 5x in the 2nd eqn \n" ); document.write( "(3y+105) + 12y = -120 \n" ); document.write( "15y = -225 \n" ); document.write( "y = -15 \n" ); document.write( "----------- \n" ); document.write( "Sub for y in any eqn and find x \n" ); document.write( " \n" ); document.write( " |