document.write( "Question 496042: Solve using the substitution method
\n" ); document.write( "1/3 x - 1/5 y = 7
\n" ); document.write( "1/6 x + 2/5 y = -4\r
\n" ); document.write( "\n" ); document.write( "Not sure how to work substitution method using fractions.
\n" ); document.write( "Need to find answer for both variables seperately.
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Algebra.Com's Answer #336306 by Alan3354(69443)\"\" \"About 
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Solve using the substitution method
\n" ); document.write( "1/3 x - 1/5 y = 7
\n" ); document.write( "1/6 x + 2/5 y = -4
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\n" ); document.write( "Then eliminate the fractions and go from there.
\n" ); document.write( "1/3 x - 1/5 y = 7
\n" ); document.write( "times 15 --> 5x - 3y = 105
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\n" ); document.write( "1/6 x + 2/5 y = -4
\n" ); document.write( "times 30 --> 5x + 12y = -120
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\n" ); document.write( "5x - 3y = 105 --> 5x = 3y + 105
\n" ); document.write( "5x + 12y = -120
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\n" ); document.write( "Sub for 5x in the 2nd eqn
\n" ); document.write( "(3y+105) + 12y = -120
\n" ); document.write( "15y = -225
\n" ); document.write( "y = -15
\n" ); document.write( "-----------
\n" ); document.write( "Sub for y in any eqn and find x
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