document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=495969>Question 495969</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A= 4x+20; B=3x<BR>\n" );
document.write( "If A is the supplement of the complement of B, solve for x. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336273 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336273\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A= 4x+20; B=3x<BR>\n" );
document.write( "If A is the supplement of the complement of B, solve for x.<BR>\n" );
document.write( ".<BR>\n" );
document.write( "\"complement of B\" = 90-3x<BR>\n" );
document.write( "\"supplement of the complement of B\" = 180-(90-3x) = 90+3x<BR>\n" );
document.write( ".<BR>\n" );
document.write( "4x+20 = 90+3x<BR>\n" );
document.write( "4x = 70+3x<BR>\n" );
document.write( "x = 70 degrees </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );